Post a New Question


posted by .

A bicycle has wheels with a diameter of 0.630 m. It accelerates uniformly and the rate of rotation of its wheels increases from 197 rpm to 300 rpm in a time of 22.5 s. Find the linear acceleration of the bicycle

  • physics -

    197 rpm = 197/60 =3.28 rev/s
    300 = 5 rev/s
    ε= (ω-ω₀)/t =(5-3.28)/22.5=0.0076 rad/s
    a = ε•R=0.0076•0.63=0.0048 m/s²

  • physics -

    you forgot to convert form from frequency to angular velocity where

    apart from that the steps are accurate

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question