Calculus...plz help!!

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find dy/dx of
xsiny-ycosx=1

  • Calculus...plz help!! -

    use the product rule....

    x(siny) - y(cosx) = 1

    x(cosy)dy/dx + siny - y(-sinx) - cosx(dy/dx) = 0
    dy/dx(xcosy - cosx) = -siny - ysinx
    dy/dx = -(siny + ysinx)/(xcosy - cosx)

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