A crate is pulled to the right with a force
of 84.5 N, to the left with a force of 116.5 N,
upward with a force of 685.7 N, and downward
with a force of 242 N.
What is the net external force in the x
direction?
To find the net external force in the x-direction, we need to determine the sum of all the forces acting in that direction.
In this case, the crate is being pulled to the right with a force of 84.5 N and to the left with a force of 116.5 N.
The net external force in the x-direction can be calculated by subtracting the force acting to the left from the force acting to the right:
Net external force in x-direction = Force to the right - Force to the left
= 84.5 N - 116.5 N
= -32 N
Therefore, the net external force in the x-direction is -32 N. The negative sign indicates that the net force is in the opposite direction of the positive x-axis.