A bullet is fired straight up from a gun with a muzzle velocity of 148 m/s.
Neglecting air resistance, what will be its displacement after 6.3 s? The acceleration of gravity is 9.8 m/s2 .
To find the displacement of the bullet after 6.3 seconds, we can use the following kinematic equation:
displacement = initial velocity * time + (1/2) * acceleration * time^2
In this case, the initial velocity of the bullet is the muzzle velocity of the gun, which is 148 m/s. The acceleration is the acceleration due to gravity, which is -9.8 m/s^2 because it acts in the opposite direction of the bullet's motion.
Now we can substitute these values into the equation:
displacement = (148 m/s) * (6.3 s) + (1/2) * (-9.8 m/s^2) * (6.3 s)^2
Simplifying this equation gives:
displacement = 148 m/s * 6.3 s - 0.5 * 9.8 m/s^2 * (6.3 s)^2
displacement = 931.2 m - 0.5 * 9.8 m/s^2 * (39.69 s^2)
displacement = 931.2 m - 0.5 * 9.8 m/s^2 * 39.69 s^2
displacement = 931.2 m - 193.3296 m
displacement = 737.8704 m
Therefore, the displacement of the bullet after 6.3 seconds is approximately 737.8704 meters.