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an altitude of triangle is 5/3rd of the length of its corresponding base if their altitude be increased by 4cm and the base is decreased by 2cm, the area of the triangles remain the same. find the base and altitude of triangle ?????

  • Shri marwari sewa sang shiksha niketan meerghat varanasi -

    math

  • math -

    let base=x
    altitude=5x/3
    area= (altitude*base)/2
    area of original triangle= (5x^2/3)/2
    according to the question
    new base=x-2
    new altitude=(5x 12)/3
    now
    area of original triangle=area of new triangle
    5x^2/3=5x^2/3-10x/3 4x-8 (1/2 is cancelled from both sides)
    now after solving we get
    x=12 that is base
    and altitude= 20

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