chemistry

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calculate the standard molar entropy change for the combustion of methane gas using S naught values from standard thermodynamic tables. Assume that liquid water is one of the products.

  • chemistry -

    CH4(g) + 2O2(g) ==> CO2(g) + H2O(l)

    dSo rxn = (n*dSo poducts) - (dSo reactants)

  • chemistry -

    I did this and the database said the answer was wrong:

    (213.8 + 70.0) - (186.2 + 2*205.0)= -312.4 j/K*mol. Am I missing something?

  • chemistry -

    I'm sorry. I didn't balance the equation. I should have written (and you should have checked)
    CH4 + 2O2 ==> CO2 + 2H2O(l)
    Try that and see if you have better luck. Thanks for letting me know. I almost always check the equations; this time I didn't and it caught me.

  • chemistry -

    Thank you!

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