A 6.0 Kg object undergoes an acceleration of 2.o m/s squared. what is the magnitude of the net external force acting on it?
F=m*a
m=6 kg
a=2 m/s^2
To find the magnitude of the net external force acting on the object, you can use Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) multiplied by its acceleration (a):
F = m * a
In this case, the mass (m) of the object is given as 6.0 kg, and the acceleration (a) is given as 2.0 m/s^2. By substituting these values into the equation, you can calculate the net external force (F):
F = 6.0 kg * 2.0 m/s^2 = 12.0 N
Therefore, the magnitude of the net external force acting on the 6.0 kg object is 12.0 Newtons.