# algebra

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A train leaves the station at 9:00 pm traveling east at 36 miles per hour. A second train leaves the station at 10:00 pm traveling west at 42 miles per hour. At what time will both trains have traveled the same distance? I need help solving it :)

• algebra -

The distance traveled by the 9:00 train from 10:00 onward is

x(9:00) = 36 + 36 * t

Where t is the time in hours after 10:00
The distance traveled by the 10:00 train
from 10:00 onward is

x(10:00) = 42 * t

Set these two equal to each other to find the time at which they have both traveled the same distance

36 + 36*t = 42 * t

36 = 6*t

t = 6 hours

Add 6 hours to 10:00

• algebra -

Simplify the expression.
22+ (32 – 42)

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