algebra

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A train leaves the station at 9:00 pm traveling east at 36 miles per hour. A second train leaves the station at 10:00 pm traveling west at 42 miles per hour. At what time will both trains have traveled the same distance? I need help solving it :)

  • algebra -

    The distance traveled by the 9:00 train from 10:00 onward is

    x(9:00) = 36 + 36 * t

    Where t is the time in hours after 10:00
    The distance traveled by the 10:00 train
    from 10:00 onward is

    x(10:00) = 42 * t

    Set these two equal to each other to find the time at which they have both traveled the same distance

    36 + 36*t = 42 * t

    36 = 6*t

    t = 6 hours

    Add 6 hours to 10:00

  • algebra -

    Simplify the expression.
    22+ (32 – 42)

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