trig
posted by Colt .
tan^2theta+6=sec^2theta+5

Are we solving for Ø ?
tan^2 Ø +6 = sec^2 Ø + 5
sin^2 Ø/cos^2 Ø + 6 = 1/cos^2 Ø + 5
times cos^2 Ø
sin^2 Ø + 6cos^2 Ø = 1 + 5 cos^2 Ø
sin^2 Ø + cos^2 Ø = 1
1 = 1
ahh, it was an identity, thus true for all values of Ø, except Ø = 90° , 270° , 450° ..... or 90° + 180k , where k is an integer.
Respond to this Question
Similar Questions

Math
1)Find cos theta if sin theta=3/5 and 90 degrees<theta<180 degrees. A)4/5 B)4/5 C)square root of 34/5 D)square root of 34/5 I chose A 2)Simplify:1csc^2theta/cot^2theta A)1 B)1 C)tan^2theta D)1/sin^4theta I chose C 3)Simplify:5(cot^2thetacsc^2theta) … 
Math
There are no typos and no work b/c I don't know how to do them. Thanks. 1)Find cos theta if sin theta=3/5 and 90 degrees<theta<180 degrees. A)4/5 B)4/5 C)square root of 34/5 D)square root of 34/5 I chose A 2)Simplify:1csc^2theta/cot^2theta … 
math
There are no typos and no work b/c I don't know how to do them. Thanks. 1)Find cos theta if sin theta=3/5 and 90 degrees<theta<180 degrees. A)4/5 B)4/5 C)square root of 34/5 D)square root of 34/5 I chose A 2)Simplify:1csc^2theta/cot^2theta … 
Calculus
What is the integral of 1tan^2theta from 0 to pi/3? 
trig
establish identity 5csc^2theta3cot^2theta=2csc^2theta+3 
Math
Prove: [(tan^2theta+1)(cos^2theta1)]=1sec^2theta 
Math
sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly sin(2theta) cos(2theta) tan(2theta) 
Math
sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly sin(2theta) cos(2theta) tan(2theta) sin(2theta) would it be 2 x (8/17) cos(2theta) would be 2 x (15/17) tan(2theta) would be 2 x … 
Precalc+trig
Solve tan(40/90) for the double angle cos(2theta). I know I use the x^2 + y^2 = r^2 formula and cos(2theta) = cos^2theta  sin^2theta. But I don't understand my answer 
Further mathemactics
Demostrate the validity of tan^2thetasin^2theta=sin^4theta sec^2theta