posted by Avery .
Two cars, 127 miles apart, start moving towards each other at the same time. One is moving 3 times as fast as the other. If they meet 1.5 hrs later, find the average speed of the slower car in miles per hour?
slower car moves 127/4 miles in 1.5 hrs
(127/4 mi) / 1.5hr = 21.17 mi/hr
Sorry, how did you get that? :(
v=s/4•t =127/4•1.5 =21.17 mph
Oh! I understand now, thanks so much to both :)