Calculus
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Find dy/dx by implicit differentiation.
x^3  3x^2y + 2xy^2 =12
Please show me the work/steps on how to do it.

x^3  (3x^2)(y) + (2x)(y^2) =12
use the product rule on the 2nd and 3rd term
3x^2  3x^2 dy/dx  6xy + 2x (2y)dy/dx + 2y^2 = 0
dy/dx(4xy  3x^2) = 6xy  3x^2  2y^2
dy/dx = (6xy  3x^2  2y^2))/(4xy  3x^2)
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