Is this right?
posted by kelly .
I have to determine the slope and y- intercept of this equation then graph
so I ended up putting it in y-mx+b form and it was 6y=4x+9 so slope is 4x and y intercept is 6y?
How would I graph it though?
I think you made a slight error in moving your variables around; the equation should look like this:
6y = 4x - 9
To have the equation in y = mx + b form, you need to make sure there is no coefficient in front of the y variable. To do this, divide both sides by 6:
y = (2/3)x - (3/2)
The slope is m, and the y-intercept is coordinate (0,b). So here the slope is 2/3 and the y-intercept is (0,1.5).
You should be able to take on the graphing from this point.