Projectiles (Physics)
posted by Soph .
Joe is analyzing a video tape of a recent world cup soccer game and made a sketch. According to the diagram what is the launch velocity of the soccer ball?
The sketch shows 2 soccer players standing 17m apart. The player standing on the left kicks the ball and it makes an angle of 40 degrees. On the right, a player is standing in front of a goal post that is 2.2 m tall.
a=acceleration
d=distance
vf= final velocity
vi=initial velocity
t=time
I know i have to split it up into a y section and an x section.
So this is what i have so far
ay=9.8
ax=0
dx=17m
vix= missing velocity x cos40
viy= missing velocity x sin40

Dx = Vo^2*sin(2A)/g = 17 m.
Vi^2*sin(80)/9.8 = = 17
Vi^2*0.10049 = 17
Vi^2 = 169.2
Vi = 13 m/s @ 40o.
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