# Physics

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On your wedding day you leave for the church 28 minutes before the ceremony is to begin, which should be plenty of time since the church is only 10.0 miles away. On the way, however, you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 14 minutes is only 5.0 mi/h. What average speed do you need for the rest of the trip to get you to the church on time?

• Physics -

s1=v1•t1= 5•0.23=1.167 mi,
s2=10-1.167 = 8.833 m
v2=s2/t2=8.833/0.23 =38.4 mi/h

• Physics -

On your wedding day you leave for the church 36 minutes before the ceremony is to begin, which should be plenty of time since the church is only 12.0 miles away. On the way, however, you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 18 minutes is only 5.0 mi/h. What average speed do you need for the rest of the trip to get you to the church on time?

• Physics -

where did you get the numbers .23 and -1.167 from?

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