math
posted by jamie .
The length of a rectangular area is 3 feet less than twice its width. The perimeter of the rectangle is 132 feet. Find the length and width of the rectangular area

P = 2L + 2W
132 = 2(2W  3) + 2W
132 = 4W  6 + 2W
132 + 6 = 6W
138 = 6W
23 = W
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