The length of a rectangular area is 3 feet less than twice its width. The perimeter of the rectangle is 132 feet. Find the length and width of the rectangular area

P = 2L + 2W

132 = 2(2W - 3) + 2W

132 = 4W - 6 + 2W

132 + 6 = 6W

138 = 6W

23 = W

To find the length and width of the rectangular area, we need to set up a system of equations based on the given information.

Let's assume the width of the rectangle is represented by "x" feet.
According to the problem, the length of the rectangle is 3 feet less than twice its width, which can be expressed as 2x - 3.

The formula for calculating the perimeter of a rectangle is:
Perimeter = 2(length + width)

In this case, the perimeter is given as 132 feet, so we can set up the equation:
132 = 2(2x - 3 + x)

Simplifying the equation, we have:
132 = 2(3x - 3)
66 = 3x - 3
69 = 3x
x = 23

Now, we have the value of the width (x) as 23 feet.
To find the length, substitute the value of x back into the expression for the length:
Length = 2x - 3
Length = 2(23) - 3
Length = 46 - 3
Length = 43

Therefore, the width of the rectangular area is 23 feet, and the length is 43 feet.