How many grams of are present in a solution if 38.60 of 0.145 solution is needed to titrate the solution?
This makes no sense.
With posts like this we need to make it a requirement that students READ their post before posting. :-)
To determine the number of grams of solute present in a solution, you need to use the given information about the volume of the solution needed for titration.
First, isolate the information about the volume of the solution needed for titration:
38.60 mL of 0.145 M solution
The number "0.145" represents the concentration. It indicates that there are 0.145 moles of solute present in 1 liter (i.e., 1000 mL) of solution.
Now, convert the volume of the solution (38.60 mL) to liters by dividing it by 1000:
38.60 mL ÷ 1000 = 0.03860 L
To find the number of moles of solute present in the solution, multiply the volume in liters by the molarity (concentration):
0.03860 L × 0.145 mol/L = 0.005593 mol
The result indicates that there are 0.005593 moles of solute in the given volume of solution.
To find the mass (in grams) of the solute, you need to know its molar mass. Let's assume the molar mass of the solute is "X" grams/mol.
Multiply the number of moles by the molar mass to find the mass:
0.005593 mol × X grams/mol = X × 0.005593 grams
Therefore, the mass in grams depends on the molar mass of the solute, for which you would need additional information.