math
posted by Melissa .
The function f(x)=ax^3x^3+bx24 has three factors. Two of these factors are x2 and x+4. Determine the values of a and b , and then determine the other factor

synthetic division yields remainders
f(x) = (x2)*p(x) + 8a+2b28
f(x) = (x+4)*q(x) + (64a4b40)
so,
8a+2b = 28
64a+4b = 40
a = 2
b = 22
f(x) = (x2)(x+4)(2x+3)
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