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I need help on both of these...

Find the exact value of cotx if the terminal side of angle x contains the point (-5,-12).

Find the exact value of secx for angle x that has a terminal side containing the point (-1,squareroot3)

  • Trigonometry -

    So the angle is in quadrant III
    tan x = -12/-5 = 12/5, so
    cot x = 5/12

    point is (-1,√3) which is in quad II
    you have a right-angled triangle with sides 1, √3, and 2 ( the famous 30-60-90 triangle)
    cos x = -1/2
    sec x = -2

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