Trigonometry
posted by james .
I need help on both of these...
Find the exact value of cotx if the terminal side of angle x contains the point (5,12).
Find the exact value of secx for angle x that has a terminal side containing the point (1,squareroot3)

First:
So the angle is in quadrant III
tan x = 12/5 = 12/5, so
cot x = 5/12
2nd:
point is (1,√3) which is in quad II
you have a rightangled triangle with sides 1, √3, and 2 ( the famous 306090 triangle)
cos x = 1/2
sec x = 2