posted by james .
I need help on both of these...
Find the exact value of cotx if the terminal side of angle x contains the point (-5,-12).
Find the exact value of secx for angle x that has a terminal side containing the point (-1,squareroot3)
So the angle is in quadrant III
tan x = -12/-5 = 12/5, so
cot x = 5/12
point is (-1,√3) which is in quad II
you have a right-angled triangle with sides 1, √3, and 2 ( the famous 30-60-90 triangle)
cos x = -1/2
sec x = -2