in isosceles angle ABC, the length of leg AB is 2x+10 and the length of the leg BC is 4x - 18. Find the length of each leg.
4x - 18 = 2x + 10
solve for x, sub back into each of the expressions, (of course they will be equal)
oh thank you very much
To find the lengths of the legs in an isosceles triangle, we need to equate the lengths of the legs.
In this case, we have:
leg AB = 2x + 10
leg BC = 4x - 18
Since it is an isosceles triangle, leg AB is equal to leg BC. So we can set up an equation:
2x + 10 = 4x - 18
To solve this equation and find the value of x, we can start by isolating the variables on one side of the equation.
Subtracting 2x from both sides gives us:
10 = 2x - 18
Next, we can isolate the x-term by adding 18 to both sides:
28 = 2x
To find the value of x, we divide both sides by 2:
x = 14
Now that we have the value of x, we can substitute it back into the expressions for the lengths of the legs:
leg AB = 2x + 10
leg AB = 2(14) + 10
leg AB = 28 + 10
leg AB = 38
leg BC = 4x - 18
leg BC = 4(14) - 18
leg BC = 56 - 18
leg BC = 38
Therefore, the length of each leg is 38 units.