physics
posted by kadeem .
Bob shoots an arrow straight up into the air at 78.5 m/s.
1)What is the maximum height of the arrows flight?
2)How long is it in the air?

1. hmax = V^2Vo^2)/2g.
hmax = (06162.25)/19.6 = 314.4 m.
2. Tr = VVo)/g = (078.5)/9.8 = 8 s. =
Rise time.
Tf = Tr = 8 s. = Fall time.
Tr + Tf = 8 + 8 = 16 s. = Time in air.
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