How many grams of hydrogen can be prepared by treating 2.63 g of iron with 130.0 mL of 1.50 M sulfuric acid solution, to give iron(III) sulfate and hydrogen?
Write and balance the equation.
Convert 2.63 g Fe to mols. mols = grams/molar mass
Convet 130.0 mL of 1.50M H2SO4 to mols. mols = M x L = ?
Using the coefficients in the balanced equation convert mols Fe to mols H2.
Do the same for H2SO4.
It is likely that the values for mols H2 will not be the same; obviously one of them must be wrong. In limiting reagent problems, which this is, the correct value is ALWAYS the smaller one and the reagent producing that value is the limiting reagent.
Then grams H2 = mols x molar mass.