The mass of the heavier block is 28 kg and the mass of the lighter blocks is 14 kg and the magnitude of the force of the connecting string on the smaller block is 24 N. Assume: g = 9.8 m/s^2 and the horizontal surface on which the objects slide is frictionless.
Determine the force F.
Answer in units of N
my last question im stuck on =/
To determine the force F, we can analyze the forces acting on the two blocks. Since the surface is frictionless, the only horizontal force acting on both blocks is the tension force in the string. This tension force is the same magnitude on both blocks because the string is inextensible.
Let's start by looking at the forces acting on the lighter block. We have the tension force T acting to the right and the gravitational force pulling the block downwards, which is given by the formula:
F_gravity = mass * acceleration due to gravity
F_gravity = 14 kg * 9.8 m/s^2
F_gravity = 137.2 N
Now, let's consider the forces acting on the heavier block. Again, we have the tension force T acting to the right, and the gravitational force pulling the block downwards:
F_gravity = mass * acceleration due to gravity
F_gravity = 28 kg * 9.8 m/s^2
F_gravity = 274.4 N
Since the tension force is the same magnitude for both blocks, we can write the equation:
T = F_gravity_lighter_block + F_gravity_heavier_block
Substituting the values we found:
T = 137.2 N + 274.4 N
T = 411.6 N
Therefore, the force F is equal to the tension force T, which is 411.6 N.