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Algebra

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An investor invested a total of $2000 in two mutual funds. One fund earned 9% profit while the other earned a 6% profit. If the investor's total profit was $129, how much was invested in each mutual fund?

  • Algebra -

    let one be $x
    the other $ (2000-x)
    .09x + .06(2000-x) = 129
    times 100
    9x + 6(2000-x) = 12900
    9x + 12000 - 6x = 12900
    3x = 900
    x=300

    $300 was invested at 9%, and 1700 was invested at 6%

    check:
    .09(300) + .06(1700) = 129

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