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Two sides of a triangle are x units and y units in length. The angle between them is theta. Prove that the area of the triangle is 1/2xysin(theta).

I'm not sure how to do this question, I tried drawing a picture but I'm still not understanding it.

  • Pre-Calculus -

    draw a perpendicular from side x to side y, let it be h
    Area of triangle
    = (1/2)base x height
    = (1/2) y h

    but sinØ = h/x
    h = xsinØ

    so area =(1/2) y xsinØ
    = (1/2)xy sinØ

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