Chemistry Pretest

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Fe can be prepared as 2 Al + Fe2O3 ----> 2 Fe + Al2O3. Suppose that 0.450 moles of Fe2O3 are reacted with an excess of Al. Suppose that 43.6 grams of Fe are obtained. What is the percent yield of Fe?

a) 16.2%
b) 60.7%
c) 86.7%
d) 43.4%


Percent yield= actual yield of product divided by theoretical yield of product times 100.

The actual yield is stated to be 43.6 g of Fe, so I just need to know how to get the theoretical yield from the information it already gives me from the problem.

  • Chemistry Pretest -

    theoritical yield: .45*(2/1) moles, so you get .90 moles Fe or .90*55 =about 50 grams in my head.

    percent yield=44/50= about 88 percnet. Answer c.

  • Chemistry Pretest -

    86.7%

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