physics

posted by .

A mass m = 76.0 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 19.7 m and finally a flat straight section at the same height as the center of the loop (19.7 m off the ground). Since the mass would not make it around the loop if released from the height of the top of the loop (do you know why?) it must be released above the top of the loop-the-loop height. (Assume the mass never leaves the smooth track at any point on its path.) It turns out the engineers designing the loop-the-loop didn’t really know physics – when they made the ride, the first drop was only as high as the top of the loop-the-loop. To account for the mistake, they decided to give the mass an initial velocity right at the beginning.
How fast do they need to push the mass at the beginning (now at a height equal to the top of the loop-the-loop) to get the mass around the loop-the-loop without falling off the track?

  • physics -

    456

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics - KE/rotation

    In Figure 11-32 (which shows a ball at the top of an incline, at the bottom of the incline a loop begins with radius R and Q a point on the loop lined up with the center of the loop), a solid brass ball of mass m and radius r will …
  2. AP Physics

    A small solid marble of mass m and radius r will roll without slipping along the loop-the-loop track if it is released from rest somewhere on the straight section of the track. For the following answers use m for the mass, r for the …
  3. physicssss

    A mass m = 73 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 17.9 m and finally a flat straight section at the same height as the center of the loop (17.9 m off the ground). Since the …
  4. physics

    A mass m = 73 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 17.9 m and finally a flat straight section at the same height as the center of the loop (17.9 m off the ground). Since the …
  5. physics

    A mass m = 76.0 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 19.7 m and finally a flat straight section at the same height as the center of the loop (19.7 m off the ground). Since the …
  6. colledge physics

    A block of mass 0.78kg starts from rest at point A and slides down a frictionless hill of height h. At the bottom of the hill it slides across a horizontal piece of track where the coefficient of kinetic friction is 0.29. This section …
  7. Physics Intro

    A roller coaster has a vertical drop of height 66 m and then is followed by a oop. It starts as a steep slope 75 degrees to the horizontal and then enters into a circular path of radius R. In order to stay below 4 tims the force of …
  8. physics

    A mass m = 88.0 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 15.8 m and finally a flat straight section at the same height as the center of the loop (15.8 m off the ground). Since the …
  9. physics

    A small block of mass 42 kg slides along a frictionless loop-the-loop track. The radius of the loop is 5 meters. At what height above the bottom of the track should the block be released from so that it just makes it through the loop-the-loop …
  10. Physics

    A mass m = 85 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 19.2 m and finally a flat straight section at the same height as the center of the loop (19.2 m off the ground). Since the …

More Similar Questions