Ethylene glycol has a specific gravity of 1.1088 at room temperature 25 degrees Celsius. What is the mass of 1.00L of ethylene glycol at this temperature?
change spgr to density: 1.1088 kg/liter
mass=denstiy*volume
To solve this problem, we need to use the formula:
Density = Mass / Volume
However, the given specific gravity of ethylene glycol is not the density but is the ratio of the density of a substance to the density of water at the same temperature. So, we first need to convert the specific gravity to density.
The specific gravity of ethylene glycol = 1.1088
The density of water at 25 degrees Celsius = 1.00 g/mL
Therefore, the density of ethylene glycol = (density of water) * (specific gravity of ethylene glycol)
= (1.00 g/mL) * (1.1088)
= 1.1088 g/mL
Now, we have the density of ethylene glycol. To find the mass of 1.00 L of ethylene glycol, we can use the conversion factor: 1 mL = 1 g.
So, the mass of 1.00 L of ethylene glycol = (density of ethylene glycol) * (volume of ethylene glycol)
= (1.1088 g/mL) * (1000 mL)
= 1108.8 grams
Therefore, the mass of 1.00 L of ethylene glycol at room temperature (25 degrees Celsius) is 1108.8 grams.