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What is the pH of a 0.50 M solution of NaNO2 if the Ka of H20x = 4.5 x 10^-4. I know that you use the Ka to find Kb and solve from there, but why?

  • Chemistry -

    Why not?
    NO2^- is a base; it attracts a H^+ from water and Kb is the strength as a base.

  • Chemistry -

    So you're saying that if you have the Ka of any acid and you can use the ionization constant of water to find Kb of its conjugate base?

  • Chemistry -

    I didn't say that in so many words but, yes, you can do that. Why? Because
    KaKb = Kw.
    If you know EITHER Ka or Kb you can calculate the other one from this relationship and Kw.

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