Post a New Question

physics

posted by .

A robot probe drops a camera off the rim of
a 437 m high cliff on Mars, where the free-fall
acceleration is 3.7 m/s
2
.
Find the velocity with which it hits the
ground.
Answer in units of m/s

  • physics -

    vf^2=2*a*h

  • physics -

    tried that...
    vf^2=2*3.7*437
    vf^2=3233.8
    vf=56.86651036

    but my teacher says its the wrong answer....

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question