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What is the net ionic equation of reaction of MgCl2 with NaOH?

I got the equation and then balanced it and then omitted the spectator ions and ended up with:

Mg(OH)2(aq)--->Mg(OH) (s)

I wanted to confirm to see if that was correct, thanks.

  • Chemistry -

    Close but no cigar.
    Full equation is
    MgCl2(aq) + 2NaOH(aq) ==> Mg(OH)2(s) + 2NaCl(aq)

    Those (aq) reagents are put in ionic form.
    Mg^2+(aq) + 2Cl^-(aq) + 2Na^+(aq) + 2OH^-(aq) ==> Mg(OH)2(s) + 2Na^+(aq) + 2Cl^-(aq)

    Then cancel 2Cl^- and 2Na^+ since they appear on both sides and you are left with
    Mg^2+(aq) + 2OH^-(aq) ==> Mg(OH)2(s)

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