a ford is traveling with a speed of 15 m/s and is 200 meters ahead of a Chevy traveling in the same directin at 20 m/s. How far will the Chevy travel before catching up to the Ford?
NEED HELP TOO
To calculate the distance the Chevy will travel before catching up to the Ford, we need to determine the time it takes for the Chevy to cover the initial distance between them.
First, let's find the relative speed of the Chevy with respect to the Ford:
Relative speed = Speed of Chevy - Speed of Ford
Relative speed = 20 m/s - 15 m/s
Relative speed = 5 m/s
Now, let's calculate the time it will take for the Chevy to catch up to the Ford:
Time = Distance / Relative speed
Time = 200 meters / 5 m/s
Time = 40 seconds
Since we now know the time it takes for the Chevy to catch up, we can find the distance it will travel in that time.
Distance = Speed of Chevy * Time
Distance = 20 m/s * 40 s
Distance = 800 meters
Therefore, the Chevy will travel 800 meters before catching up to the Ford.
To find the distance the Chevy will travel before catching up to the Ford, we need to determine the time it will take for the Chevy to cover the initial distance between them, which is 200 meters.
Let's consider the relative velocity between the Chevy and the Ford. The relative velocity is calculated by subtracting the Ford's velocity from the Chevy's velocity because they are moving in the same direction.
Relative velocity = Chevy's velocity - Ford's velocity
Relative velocity = 20 m/s - 15 m/s
Relative velocity = 5 m/s
Now, we can calculate the time it will take for the Chevy to cover the initial distance between them using the relative velocity.
Time = Distance / Relative velocity
Time = 200 meters / 5 m/s
Time = 40 seconds
Therefore, the Chevy will take 40 seconds to catch up to the Ford and during this time, it will also travel the same distance. Let's calculate that.
Distance traveled by the Chevy = Chevy's velocity * Time
Distance traveled by the Chevy = 20 m/s * 40 s
Distance traveled by the Chevy = 800 meters
Hence, the Chevy will travel 800 meters before catching up to the Ford.
The distance between the cars decreases at a rate of 5 m/s.
If the separation starts at 200 m, and decreases at 5 m/s, the time required is 200/5 = ___ s