A ball is dropped from the roof of a building. How fast is it moving after 4.6 seconds?
10
To determine the speed of the ball after 4.6 seconds, we can use the principles of kinematics and the laws of motion.
First, we need to know the acceleration due to gravity, denoted as "g." On Earth, the acceleration due to gravity is approximately 9.8 m/s^2.
Next, we can use the equation of motion for vertical motion:
v = u + gt
In this equation:
- v represents the final velocity (what we are trying to find),
- u is the initial velocity (in this case, the ball is dropped, so the initial velocity is 0 m/s),
- g is the acceleration due to gravity (9.8 m/s^2),
- t is the time taken (4.6 seconds).
Plugging in the values into the equation, we have:
v = 0 + (9.8 m/s^2)(4.6 s)
v = 0 + 44.68 m/s
v ≈ 44.68 m/s
Therefore, the ball would be moving at approximately 44.68 m/s after 4.6 seconds of being dropped.