You push a 8.00 kg suitcase across a smooth horizontal floor applying a force directed 31.5 degrees below the horizontal. Someone measures the acceleration of the suitcase to be 1.73 m/s2.
Assuming g = 10.0 m/s2, what is the normal force the ground exerts on the suitcase?
Fap*cosA = ma.
Fap*cos31.5 = 8*1.73
0.853Fap = 13.84
Fap = 16.23 N @ 31.5o. = Force applied.
Ws = mg = 8.0kg * 10N/kg = 80 N. = Wt.
of suitcase.
Fn = Ws + Fap*sin31.5.
Fn = 80 + 16.23*sin31.5 = 88.5 N. = Normal force.