a 225.0 gram sample of aluminum is heated and the temperature increased from 50.0 celsius to 65.0 celsius for temperature change of 15.0 celsius. how many calories of heat was absorbed to produce this temperature change?
q in calories = mass Al x specific heat Al x delta T.
To find the amount of heat absorbed (in calories), you can use the specific heat capacity formula:
Heat = mass × specific heat capacity × temperature change
First, we need to find the specific heat capacity of aluminum. The specific heat capacity is the amount of heat energy required to raise the temperature of 1 gram of a substance by 1 degree Celsius.
The specific heat capacity of aluminum is 0.897 cal/g°C.
Now, we can calculate the heat absorbed by the aluminum sample:
Heat = mass × specific heat capacity × temperature change
Heat = 225.0 g × 0.897 cal/g°C × 15.0°C
Now, let's do the math:
Heat = 3028.025 cal
Therefore, 225.0 grams of aluminum absorbed approximately 3028.025 calories of heat to produce a temperature change of 15.0 degrees Celsius.