can someone explain how to do this problem, please.
6x^2 + 13x +2 + 0
6x^2 + 13x +2 =0
I suspect you mean
we need two things that add to 13 and use 6 and 2
try 6 * 2 and 1
(6x + 1)(x+ 2) = 0
x = -1/6 or x = -2
thanks
Certainly! The given problem is a quadratic expression: 6x^2 + 13x + 2 = 0. To solve this quadratic equation and find the values of x, we can use factoring, completing the square, or the quadratic formula.
Let's start with factoring. In this case, factoring may not yield easily recognizable factors for the quadratic expression. So, let's move on to the quadratic formula.
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Here's how to use the quadratic formula to solve for x:
In our case, a = 6, b = 13, and c = 2. We substitute these values into the formula:
x = (-(13) ± √((13)^2 - 4(6)(2))) / (2(6))
Now, simplify the expression inside the square root:
x = (-13 ± √(169 - 48)) / 12
x = (-13 ± √121) / 12
x = (-13 ± 11) / 12
Completing the calculations gives us two possible solutions for x:
x = (-13 + 11) / 12 = -2/12 = -1/6
x = (-13 - 11) / 12 = -24/12 = -2
So, the solutions to the quadratic equation 6x^2 + 13x + 2 = 0 are x = -1/6 and x = -2.