A person weighing 0.6 kN rides in an elevator that has a downward acceleration of 2.3 m/s^2.

The acceleration of gravity is 9.8 m/s^2.
What is the magnitude of the force of the elevator floor on the person?
Answer in units of kN

Since you know the Fg (which is 0.6kN * 1000 = 600N), you can use that to find the mass of the object:

mg = Fg
mg = 600
m(9.8) = 600
m = 61.2
Now, you use the sum of forces formula, keeping in mind that you have 2 forces in the vertical direction: Ft and Fg. MAKE DOWN THE POSITIVE DIRECTION, THIS WILL HELP YOU LATER ON
F = ma
Fg - Ft = (61.2)(2.3) --> (acceleration was given, and Fg is positive b/c we made down the positive direction)
600 - Ft = (61.2)(2.3)
Ft = 459 N ==> 0.459 kN

thanks

Well, let's calculate this with the help of Newton's second law of motion. The weight of the person can be calculated using the equation:

weight = mass x acceleration due to gravity

Given that the acceleration due to gravity is 9.8 m/s^2 and the weight is 0.6 kN, we can find the mass of the person:

0.6 kN = mass x 9.8 m/s^2

Rearranging the equation:

mass = 0.6 kN / 9.8 m/s^2

Now, let's find the mass:

mass ≈ 0.0612 kg

Since the elevator is accelerating downwards with 2.3 m/s^2, we need to consider this additional acceleration in the equation. The net downward force acting on the person is:

force_net = mass x (acceleration due to gravity + acceleration of the elevator)

force_net = 0.0612 kg x (9.8 m/s^2 + 2.3 m/s^2)

force_net = 0.0612 kg x 12.1 m/s^2

force_net ≈ 0.742 kN

So, the magnitude of the force of the elevator floor on the person is approximately 0.742 kN. That's quite a weight to carry, although hopefully, the elevator floor is strong enough to handle it!

To find the magnitude of the force of the elevator floor on the person, we need to consider the forces acting on the person in the elevator.

The first force we need to consider is the force due to gravity. The person has a weight of 0.6 kN, which is the force exerted by gravity on the person.

Since the elevator is accelerating downwards, there is an additional downward force on the person. This is the force due to the acceleration of the elevator. The magnitude of this force can be calculated using Newton's second law, which states that force is equal to mass times acceleration.

The mass of the person can be calculated using the formula weight = mass × acceleration due to gravity. Rearranging the equation, we have mass = weight / acceleration due to gravity. Plugging in the values, we get:

mass = 0.6 kN / 9.8 m/s^2 = 0.0612 kg.

Now, we can calculate the force due to the acceleration of the elevator. Using Newton's second law, we have:

force = mass × acceleration.

Plugging in the values, we get:

force = 0.0612 kg × 2.3 m/s^2 = 0.14076 N.

To convert this force to kilonewtons (kN), we divide by 1000:

force = 0.14076 N / 1000 = 0.00014076 kN.

Therefore, the magnitude of the force of the elevator floor on the person is approximately 0.000141 kN.

m = 600/g = 61.2 kg

force up on object = F
force down on object = m g = 600 N

net force up = F-600

F = m a
F-600 = 61.2 (-2.3)
F = 600 - 141 = 459 N = .459 kN