Physics
posted by sam .
A person weighing 0.6 kN rides in an elevator that has a downward acceleration of 2.3 m/s^2.
The acceleration of gravity is 9.8 m/s^2.
What is the magnitude of the force of the elevator ﬂoor on the person?
Answer in units of kN

m = 600/g = 61.2 kg
force up on object = F
force down on object = m g = 600 N
net force up = F600
F = m a
F600 = 61.2 (2.3)
F = 600  141 = 459 N = .459 kN
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