posted by Pcwest .
Two ships leave the same port at 7.am. The first ship sails towards europe on a 54 degree course at a constant rate of 36 mi/h. The second ship,neither a tropical destination, sails on a 144 degree course at a constant speed of 42 mi/h. Find the distance between the ships at 11. Am.
I hope this helps anyone.
Draw a triangle with an angle of 54 degrees. Then include the 54 degree angle in the 144 degree angle. Hope this makes sense.
Angle 144 overlaps angle 54.
So the angle of the distance between the ships is 90.
Then use the law of cosines
the final answer is 221.27 miles