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analytical chemisty

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Calculate the pH and pOH of a 0.00002M solution of acetic acid.

  • analytical chemisty -

    Call acetic acid HAc.
    ............HAc ==> H^+ + Ac^-
    initial..2E-5M......0.......0
    change....-x........x........x
    equil...2E-5-x......x........x

    Ka = (H^+)(Ac^-)/(HAc)
    Substitute and solve for H^+, then
    pH = -log(H^+).
    Then pH + pOH = pKw = 14
    Youknow pH and pKw, solve for pOH.

    Note: I think you must solve the quadratic; i.e., you will not be able to make simplifying assumptions.

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