Need to write a brief description of the procedure required to make 900mL of a 0.5 M NaCl solution. The formula weight of NaCl is 58.4g/mole.

26.28 g NaCl

this dont help

first measure g then measure

To make a 0.5 M NaCl solution with a volume of 900 mL, you will need to follow these steps:

1. Calculate the number of moles of NaCl needed:
Moles of NaCl = (Molarity) x (Volume in liters)
Moles of NaCl = 0.5 mol/L x 0.9 L
Moles of NaCl = 0.45 moles

2. Convert moles of NaCl to grams:
Grams of NaCl = (Moles of NaCl) x (Formula weight of NaCl)
Grams of NaCl = 0.45 moles x 58.4 g/mol
Grams of NaCl = 26.28 grams

3. Weigh out 26.28 grams of NaCl using a balance.

4. Transfer the weighed NaCl into a container or beaker.

5. Add distilled water gradually to the container, while stirring continuously until the volume reaches 900 mL.

6. Ensure that the NaCl is completely dissolved in the solution by observing that no solid NaCl particles remain.

7. Once the solution is prepared, it is essential to properly label it with the concentration, date, and any other necessary information.

By following these steps, you can make a 0.5 M NaCl solution with a volume of 900 mL.