How much heat is necessary to change 5 grams of water at 10 degrees celcius to water at 70 degrees celcius?
Note the correct spelling of celsius.
q = mass x specific heat x (Tfinal-Tinitial)
150g will dissolve
To determine the amount of heat required to change the temperature of a substance, you need to use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in joules/gram°C)
ΔT = change in temperature (final temperature - initial temperature) (in °C)
In this case, we are dealing with water, which has a specific heat capacity of approximately 4.18 J/g°C.
Given:
m = 5 grams (mass of water)
c = 4.18 J/g°C (specific heat capacity of water)
ΔT = 70°C - 10°C = 60°C (change in temperature)
Now, we can calculate the heat energy (Q) required:
Q = 5g * 4.18 J/g°C * 60°C
Q = 1254 J
Therefore, it would require approximately 1254 joules of heat energy to change 5 grams of water at 10°C to water at 70°C.