1.Turner’s treadmill starts with a velocity of

−2.4 m/s and speeds up at regular intervals
during a half-hour workout.After 23 min, the
treadmill has a velocity of −7.0 m/s.
What is the average acceleration of the
treadmill during this period?
Answer in units of m

To find the average acceleration of the treadmill during the given period, we need to use the formula for average acceleration:

Average acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = -2.4 m/s
Final velocity (v) = -7.0 m/s
Time (t) = 23 minutes = 23 * 60 seconds = 1380 seconds

Substituting the values into the formula:

Average acceleration = (-7.0 - (-2.4)) / 1380

Simplifying further:

Average acceleration = (-7.0 + 2.4) / 1380

Average acceleration = -4.6 / 1380

Average acceleration ≈ -0.0033 m/s^2

To find the average acceleration, we need to use the formula:

average acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = -2.4 m/s
Final velocity (v) = -7.0 m/s
Time (t) = 23 min = 23 * 60 = 1380 seconds

Substituting the values into the formula:

average acceleration = (-7.0 - (-2.4)) / 1380

Simplifying:

average acceleration = (-7.0 + 2.4) / 1380

average acceleration = -4.6 / 1380

average acceleration ≈ -0.0033 m/s²

Therefore, the average acceleration of the treadmill during this period is approximately -0.0033 m/s².