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If 15.0g of KCL is added to 100.0g of water at 30.0 C, how much more must be added to saturate the solution
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The solubility of KCl at 30 C is what?
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If 15.0 g of KCl is added to 100.0 g of water at 30.0 °C, how much more must be added to saturate the solution?
Top answer:
What's the solubility of KCl at 30.0 C?
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If 15.0g of KCL is added to 100.0g of water at 30.0 C, how much more must be added to saturate the solution
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35 C
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To prepare 1.000 kg of 5.5 percent by mass KCl (aq), one may dissolve
a. 994.5 g KCl in 5.5 g of water b. 5.5 g KCl in 994.5 g of
Top answer:
5.5% by mass means 5.5 g KCl + 94.5 g H2O = 100 g solution. Just multiply by 10 to obtain 55 g KCl +
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A KCl solution containing 42g of KCl per 100.0 g of water is cooled from 60 C to 0 C . What will happen during cooling?
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During the cooling process, several things will happen to the KCl solution: 1. The temperature of
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A KCl solution containing 42g of KCl per 100.0 g of water is cooled from 60 C to 0 C . What will happen during cooling?
Top answer:
Since the solubility of KCl is about 45 g at 60 ∘C, a KCl solution containing 42 g in 100 g of
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A KCl solution containing 42g of KCl per 100.0 g of water is cooled from 60 C to 0 C . What will happen during cooling?
Top answer:
the water will freeze
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If 32.3 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass?
5.94% KCl
Top answer:
To find the concentration of a solution in percent by mass, you need to divide the mass of the
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a solution of kcl contains 10. grams of kcl in 100. ml of water at 30c. how many additional grams of kcl are needed to saturate
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I don't have all of the solubility tables memorized for all of the salts. There must be thousands.
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Can someone check my answer and let me know me if the are right or wrong.
1. What is the maximum amount of KCl that can dissolve
Top answer:
Sure, I can check your answers for you. Let's go through each question and determine if your answer
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If 18.4 mL of a 1.37 M aqueous KCl solution was placed in a 150-mL volumetric flask and water was added to dilute to the mark,
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mols = M x L = 1.37 x 0.0184 = ? You can have 3 significant figures in the answer.
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