how much heat is needed to warm 200 grams of water from an initial temperature 24 celsius to 84 celsius
To determine the amount of heat needed to warm a given amount of water, you can use the specific heat capacity formula:
Q = m * c * ΔT,
where:
Q is the heat energy (in Joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C),
ΔT is the change in temperature (in °C).
For water, the specific heat capacity is approximately 4.18 J/g°C.
Let's calculate the amount of heat energy required to warm 200 grams of water from 24°C to 84°C:
ΔT = 84°C - 24°C = 60°C
Q = (200 g) * (4.18 J/g°C) * (60°C)
Q = 50,160 J
Therefore, approximately 50,160 Joules (J) of heat energy are needed to warm 200 grams of water from 24°C to 84°C.