Dan drops a stone down a well and sees it hit the water 1.2 sec later.
A. how deep is the well (no air resistance)
B. What is the speed of impact of the stone?
c.If Dan drops an elephant down the well how long will it take to hit the water? Explain
Thanks for the help!
To answer these questions, we can use the basic equations of motion. Let's go through each question step by step:
A. How deep is the well?
To find the depth of the well, we can use the formula for the distance traveled by an object in free fall:
d = (1/2) * g * t^2
In this equation, d represents the depth of the well, g is the acceleration due to gravity (which is approximately 9.8 m/s^2 on Earth), and t is the time taken to hit the water (which is given as 1.2 seconds).
Plugging in the values, we can calculate:
d = (1/2) * 9.8 * (1.2)^2
= (1/2) * 9.8 * 1.44
= 7.056 meters
So, the depth of the well is approximately 7.056 meters.
B. What is the speed of impact of the stone?
To find the speed of impact, we can use the formula for velocity in free fall:
v = g * t
Using the same values as before, we can calculate:
v = 9.8 * 1.2
= 11.76 m/s
So, the speed of impact of the stone is approximately 11.76 m/s.
C. If Dan drops an elephant down the well, how long will it take to hit the water?
To solve this, we need to assume no air resistance and that the acceleration due to gravity remains constant. In reality, the elephant's size and mass would affect the result, but for simplicity, we'll assume it doesn't.
Since the acceleration due to gravity is the same for all objects, the time taken for the elephant to hit the water will be the same as that of the stone: 1.2 seconds.
Keep in mind that this answer is based on the simplifying assumptions made, and in reality, factors like air resistance and the elephant's shape and size would influence the actual time taken.