how much negative work is done by friction on a 2000-kg car if you slow down from 20 m/s to 10 m/s?
the work done on the car is reflected by the change in kinetic energy
w = [.5 * 2000 * 20^2] - [.5 * 2000 * 10^2]
the units are joules
w = [.5 * 2000 * 20^2] - [.5 * 2000 * 10^2]
the units are joules