A solid of density 5000 kg/m^3 weighs 0.5 kgf in air.It is completely immersed in water of density 1000 kg/m^3. Calculate the apparent weight of the solid in water.

We have,

Density of solid, d = 5000 kg/m3

Weight in air, W = 0.5 kgf = 0.5g N

Density of water, q = 1000 kg/m3

Let, V be the volume of the solid.

So, W = Vdg

=> 0.5g = V × 5000 × g

=> V = 10-4 m-3

So, Buoyant force is, B = Vqg = 10-4 × 1000 × g = 0.1 g N = 0.1 kgf

Thus, apparent weight = W – B = 0.5 – 0.1 = 0.4 kgf

45kg

0.5g

0.4kgf

A solid of density of 5000kg m^3 weighs 0.5 kg f in air is completely immersed in the liquid of density 8000 kg m^3 calculate the apparent weight of solid in liquid

To calculate the apparent weight of the solid in water, we need to understand the principles of buoyancy.

Buoyancy is the force exerted by a fluid on an object submerged in it. It is equal to the weight of the fluid displaced by the object. When an object is fully submerged, the upward buoyant force is equal to the weight of the object. If the upward buoyant force is greater than the weight of the object, the object will float. If it is less, the object will sink.

In this case, the solid is fully submerged in water. To calculate the apparent weight, we need to determine the buoyant force on the solid.

Step 1: Calculate the weight of the solid in air.
Given: Density of the solid (ρsolid) = 5000 kg/m^3
Weight of the solid in air = 0.5 kgf

Since weight is the force due to gravity, we can convert kgf to Newtons (N) using the conversion factor: 1 kgf = 9.81 N.
Therefore, the weight of the solid in air = 0.5 kgf * 9.81 N/kgf = 4.905 N.

Step 2: Calculate the weight of the displaced water.
The weight of the displaced water is equal to the buoyant force acting on the solid.
The volume of the displaced water is the same as the volume of the solid, as the solid is fully submerged.

The mass of the solid can be calculated using the formula: mass = volume * density.
Given: Density of water (ρwater) = 1000 kg/m^3
Density of the solid (ρsolid) = 5000 kg/m^3

Let's assume the volume of the solid is V cubic meters.
mass of the solid = V * ρsolid
mass of the water displaced = V * ρwater

The weight of the displaced water = mass of the water displaced * acceleration due to gravity (g)
Let's assume the acceleration due to gravity, g = 9.81 m/s^2.

The weight of the displaced water = V * ρwater * g

Step 3: Calculate the apparent weight of the solid in water.
The apparent weight of the solid in water is the difference between the weight of the solid in air and the weight of the displaced water.

Apparent weight of the solid in water = Weight of the solid in air - Weight of the displaced water
Apparent weight of the solid in water = 4.905 N - V * ρwater * g

To get the value of V, we need more information about the solid, such as its dimensions or shape. With that information, we can calculate the volume of the solid and substitute it into the above equation to find the apparent weight of the solid in water.

volume=.5kg/5000kg/m3= 100ml

mwass water displaced=100g

apparent mass=origianal-displaced=400g