Someone in a car going past you at the
speed of 23 m/s drops a small rock from a
height of 1.9 m.
How far from the point of the drop will the
rock hit the ground? The acceleration due to
gravity is 9.8 m/s
2
.
Answer in units of m
To find the distance from the point of the drop where the rock hits the ground, you can use the equations of motion. In this case, since the rock is dropped vertically, we can use the equation:
s = ut + (1/2)at^2
Where:
s = distance traveled
u = initial velocity (in this case, 0 m/s since the rock is dropped)
a = acceleration due to gravity (9.8 m/s^2)
t = time taken
First, let's find the time taken for the rock to hit the ground. We know the initial velocity is 0 m/s and the final velocity will be when the rock hits the ground, so we can use the equation:
v = u + at
0 = 0 + 9.8t
t = 0 s
The time taken for the rock to hit the ground is 0 seconds.
Next, let's substitute the time value into the equation to find the distance traveled:
s = 0(0) + (1/2)(9.8)(0)^2
s = 0
Therefore, the rock will hit the ground at a distance of 0 meters from the point of the drop.