posted by Matt .
What volume of 3.16 M HNO3 is required to
prepare 524 mL of a 0.2 M HNO3 solution?
Answer in units of mL.
How many moles do you want? That's M x L = ?
Then M HNO3 = mols HNO3/L HNO3. You know M and mols. Solve for L and convert to mL.
So is it 1655.84?
Not even close. Post your work and I'll find your error.
I converted my 524ml to liters so that became 524000. Then I did 3.16x1655.84. Then converted back to liters. But i just realized i skipped a step, but I don't understand where I get the numbers at for that.
524 mL = 0.524 L
mols you need = M x L = 0.2 x 0.524 = 0.104
Then M = mols/L or
3.16M = 0.104/L so L = 0.104/3.16 = 0.03316 L or 33.16 mL.
We're allowed only three significant figures; therefore, I would round that to 33.2 mL.
You may find it easier to use the dilution formula.
c1v1 = c2v2
0.2 x 524 = 3.16 x v2
v2 = (0.2*524/3.16) = 33.2 mL.