When 0.055 moles of lead(II) nitrate are dissolved in enough water to make 803 mililiters of solution, what is the molar concentration of nitrate ions?
Answer in units of M.
To find the molar concentration of nitrate ions (NO3-) in the solution, we first need to determine the number of moles of nitrate ions present.
In order to do that, we need to understand that each mole of lead(II) nitrate (Pb(NO3)2) contains two moles of nitrate ions (NO3-). This means that we have 0.055 moles of lead(II) nitrate, which will result in 2 * 0.055 = 0.11 moles of nitrate ions.
Now, we have the number of moles of nitrate ions, we can find the molar concentration. Molar concentration is defined as moles of solute divided by the volume of the solution in liters.
Given that the volume of the solution is 803 milliliters, we need to convert it to liters by dividing it by 1000: 803 mL / 1000 = 0.803 L
Now, we can calculate the molar concentration of nitrate ions by dividing the number of moles of nitrate ions (0.11 moles) by the volume of the solution in liters (0.803 L).
Molar concentration = moles of nitrate ions / volume of solution in liters
Molar concentration = 0.11 moles / 0.803 L
Calculating this, we find that the molar concentration of nitrate ions is approximately 0.137 M (rounded to three decimal places).
Therefore, the molar concentration of nitrate ions in the solution is 0.137 M.
To find the molar concentration of nitrate ions in the solution, we first need to calculate the number of moles of nitrate ions in lead(II) nitrate.
The chemical formula of lead(II) nitrate is Pb(NO3)2. From the formula, we can see that for every one mole of lead(II) nitrate, there are two moles of nitrate ions (NO3-).
Given that there are 0.055 moles of lead(II) nitrate, we can multiply this by the ratio of nitrate ions to lead(II) nitrate:
0.055 moles Pb(NO3)2 * (2 moles NO3- / 1 mole Pb(NO3)2) = 0.11 moles NO3-
So, we have 0.11 moles of nitrate ions.
Now to find the molar concentration, we need to divide the number of moles of nitrate ions by the volume of the solution:
Molar concentration (M) = moles of solute / volume of solution (in liters)
Given that the volume of the solution is 803 milliliters, we need to convert it to liters:
803 milliliters * (1 liter / 1000 milliliters) = 0.803 liters
Now we can calculate the molar concentration:
Molar concentration (M) = 0.11 moles / 0.803 liters = 0.138 M
Therefore, the molar concentration of nitrate ions is 0.138 M.
mols Pb(NO3)2 = grams/molar mass
Then M NO3^- = 2x that.