suppose the density of 100.0 mL of some liquid was found to be 0.815 g/mL. What would be the specific gravity of 20.0 mL of this liquid?
You don't list temperature; therefore, I will assume the density of water at whatever T this is to be 1.00 g/mL. The specific gravity is 1.00.
1.0g/vm
To find the specific gravity of a liquid, we need to compare it to the specific gravity of water. The specific gravity is defined as the ratio of the density of a substance to the density of water at the same temperature and pressure.
In this case, we have the density of the liquid (0.815 g/mL) and we need to find the specific gravity of 20.0 mL of this liquid.
To calculate the specific gravity, we need to first determine the density of water at the same temperature and pressure. The density of water is 1.0 g/mL at standard temperature and pressure (STP).
Next, we can set up a proportion using the densities:
Density of liquid / Density of water = Specific gravity of liquid / 1
Now, let's substitute the given values:
0.815 g/mL / 1.0 g/mL = Specific gravity of liquid / 1
To solve for the specific gravity of the liquid, we cross-multiply and solve for it:
Specific gravity of liquid = (0.815 g/mL) / (1.0 g/mL) = 0.815
Therefore, the specific gravity of 20.0 mL of this liquid would be 0.815.